Completing the Square and Solving Quadratic Equations
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Question 4
You transformed the quadratic equation
y=x2+4x+3y equals x squared plus 4 x plus 3
into its vertex form
y=(x+2)2−1y equals the quantity x plus 2 squared minus 1.
Fill in the blanks to find the zeros of the quadratic equation.
y=(x+2)2−1y equals the quantity x plus 2 squared minus 1
Set the equation equal to zero (y=0): (x+2)2−1=0The quantity x plus 2 squared minus 1 equals zero
Add 1 to both sides of the equation: (x+2)2=1The quantity x plus 2 squared equals 1
Square root both sides of the equation: x+2=±√1square root of 1x plus 2 equals plus or minus the square root of 1
Simplify and solve for x: x=-negative2±1x equals negative 2 plus or minus 1
x=-negative3and-negative1x equals negative 3 and negative 1 Incorrect. Refer to the ‘Steps for Solving Quadratic Equations in Vertex Form’ to help you, and try again.