Solve for the zeros of the quadratic equation y=-negative3(x+1)2+7y equals negative 3 times the quantity x plus 1 squared plus 7.
Click each step to see how this is done.
Step 1: Set the equation equal to zero.
y=-negative3(x+1)2+7y equals negative 3 times the quantity x plus 1 squared plus 7
-negative3(x+1)2+7=0negative 3 times the quantity x plus 1 squared plus 7 equals 0
Step 2: Isolate the parentheses.
-negative3(x+1)2+7=0negative 3 times the quantity x plus 1 squared plus 7 equals 0
(x+1)2=73the quantity x plus 1 squared equals 7 thirds
Step 3: Square root both sides of the equation.
(x+1)2=73the quantity x plus 1 squared equals 7 thirds
√(x+1)2=±√73the square root of the quantity x plus 1 squared equals plus or minus the square root of 7 thirds
Step 4: Simplify.
√(x+1)2=±√73the square root of the quantity x plus 1 squared equals plus or minus the square root of 7 thirds
x+1=±√73x plus one equals plus or minus the square root of seven thirds
Step 5: Solve for x.
x+1=±√73x plus one equals plus or minus the square root of seven thirds
x=-negative1±√73x equals negative one plus or minus the square root of seven thirds
x≈-negative2.5275 and 0.5275x equals approximately negative 2 and five thousand two hundred seventy five ten thousandths and zero and five thousand two hundred seventy five ten thousandths