Consider the function f(x)f of x, shown on the xy-coordinate plane. Identify the equation that will transform f(x)f of x to the function g(x)g of x, as shown.
Identify the equation in the form g(x)=af(x+h)+kg of x equals a times f of the quantity x plus h plus k. Enter a number into each of the blanks.
Answer:Correct! Go to question 2.Incorrect. The answer is
g(x)=1f(x+-negative6)+-negative4g of x equals one times f of the quantity x plus negative six plus negative four.
The function f(x)f of x translated to the right 6 units. This is done by adding -negative6 to the domain (x) of f(x)f of x, in other words, f(x+-negative6)f of the quantity x plus negative six. Then, f(x)f of x shifted down 4 units. This is done by adding -negative4 to the function f(x+-negative6)f of the quantity x plus negative 6, giving us f(x+-negative6)+-negative4f of the quantity x plus negative 6 plus negative four. The function f(x)f of x did not dilate (stretch) or reduce (shrink) as it transformed to become g(x)g of x. You can check this by measuring the distance between specific points along the two parabolas.
Therefore, g(x)=1f(x+-negative6)+-negative4g of x equals one times f of the quantity x plus negative six plus negative four.
Go to question 2.
One or more of your answers are incorrect. Try again. How has the parent function f(x)f of x transformed to form the function g(x)g of x? What operations viewed in the videos cause these transformations?
